For a circuit arrangement shown in figure, energy stored will be

Options

A. 0.54 J
B. 0.36 J
C. 0.24 J
D. 0.18 J

Answer

D

Explanation

Effective capacitance
`(1)/(C)=(1)/(4)+(1)/(4)+(1)/(8)impliesC=(8)/(5)mF`
Energy stored`=(1)/(2)CV^(2)`
`=(1)/(2)xx(8)/(5)xx10^(-3)xx15xx15=1.85J`