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An AC source is in series with R and L. ...

An AC source is in series with R and L. if the respective potetntial drops are 200 V and 150 V, the applied voltage will be

A

500 V

B

25 V

C

250 V

D

350 V

Text Solution

Verified by Experts

The correct Answer is:
C
The applied voltage is,
`V=sqrt(V_(R)^(2)+V_(L)^(2))`
`=sqrt((200)^(2)+(150)^(2))=250V`
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