The pressure and temperature of `4dm^(3)` of carbon dioxide gas are doubled. Then, volume of carbon dioxide gas would be

Options

A. `2dm^(3)`
B. `3dm^(3)`
C. `4dm^(3)`
D. `8dm^(3)`

Answer

C

Explanation

`(p_(1)V_(1))/(T_(1))=(p_(2)V_(2))/(T_(2))implies(p_(1)xx4)/(T_(1))=(2p_(1)xxV_(2))/(2T_(1))`
`2V_(2)=8=4dm^(3)`