In the incorrect statement/s among the following is/are
I. `NCl_(5)` does not exist while `PCl_(5)` does
II. Lead prefers to form tetravalent compound as compare to bivalent.
III. The three C-O bonds are not equal in the carbonate ion
IV. Both `O_(2)^(+)` and NO are paramagnetic

Options

A. I,III and IV
B. I and IV
C. II and III
D. I and III

Answer

C

Explanation

(I) in nitrogen, d-orbitals are absent, so it does not form `NCl_(5)`. Pclsexist due to presence of d-orbitals
(II) `Pb^(2+)` is more stable than `Pb^(4+)`, due to inert pair effect.
(III) IN carbonate ion `(CO_(3)^(2-))` all the three C-O bonds are identical due to resonance.
(VI) `._(2)^(+)(8+8+-1=15)=sigma1s^(2),sigma^(**)1s^(2),sigma2s^(2),simga^(**)2s^(2),sigma2p_(x)^(2),pi2p_(y)^(2)`
`=pi2p_(z)^(2),pi2p_(y)^(1)`
NO(7+8=15)
Hence, both `O_(2)^(+)` and NO contains one unpareid electron, so paramagnetic.