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A car is moving on a circular track of r...

A car is moving on a circular track of radius 0.1 km with a speed 60 km/h, angle of banking would be

A

`tan^(-1)(1//18)`

B

`tan^(-1)(5//18)`

C

`cos^(-1)(5//18)`

D

`tan^(-1)(18//5)`

Text Solution

Verified by Experts

The correct Answer is:
B
Angle of banking
`theta=tan^(-1)((v^(2))/(rg))`
`=tan^(-1)(((60xx5//18)^(2))/(0.1xx1000xx10))`
`tan^(-1)(5//18)`
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