A particle moves from position 3hati+2ha...

A particle moves from position `3hati+2hatj+6hatk` to `14hati+13hatj+9hatk` due to a uniform force of `4hati+hatj+3hatk`. Find the work done I the displacement is in metre.

16 J

64 J

32 J

48 J

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The correct Answer is:

Work done
`W=F*d`
`=(4hati+hatj+3hatk).[(14hati+13hatj+9hatk)-(3hati+2hatj+6hatk)]`
`=(4hati+hatj+3hatj)*[(14-3)hati+(13-2)hatj+(9-6)hatk]`
`=(4hati+hatj+3hatk)*(11hati+11hatj+3hatk)`
`=44+11+9=64J`

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