The adjoining figure shows two bulbs `B_(1)` and `B_(2)` resistor `R` and an inductor and `L`. When the switch `S` is turned off

Options

A. `B_(1)` dies out immediately but `B_(2)` will with some delay
B. `B_(2)` dies ou immediately but `B_(1)` with some delay
C. Both `B_(1) and B_(2)` will dies out immediately
D. Both `B_(1) and B_(2)` will die out with some delay

Answer

A

Explanation

From the given circuit diagram it is clear that R is connected in series with `B_(1)`.
`therefore` Current in `B_(1)` becomes zero immediately. But L is connected in series with `B_(2)`. The decay of current in L is exponential, hence `B_(2)` stops glowing after sometime.