Arrange the following ions in the order of decreasing `X-O` bond length where X is the central atom:

Options

A. `ClO_(4)^(-) gt SO_(4)^(2-) gt PO_(4)^(3-) gt SiO_(4)^(4-)`
B. `SiO_(4)^(4-) gt PO_(4)^(3-) gt SO_(4)^(2-) gt ClO_(4)^(-)`
C. `SiO_(4)^(4-) gt PO_(4)^(3-) gt ClO_(4)^(-)gt SO_(4)^(2-)`
D. `SiO_(4)^(5-) gt SO_(4)^(2-) gt PO_(4)^(3-) gt ClO_(4)^(-)`

Answer

B

Explanation

As the number of double bonds increases, X-O bond length decreases.

hence, the order of X-O bond length is
`SiO_(4)^(4-)gtPO_(4)^(3-)gtSO_(4)^(2-)gtClO_(4)^(-)`