A given sample of milk turns sour at room temperature `(27^(@)C)` in five hours. In a refrigerator at `-3^(@)C`, it can be stored 10 times longer. The energy of acrivation for the souring of milk is

Options

A. `2.303xx10R" "kJ//mol`
B. `2.303xx5R" R "kJ//mol`
C. `2.303xx3" R "kJ//mol`
D. `2.303xx2.7" R "kJ//mol`

Answer

D

Explanation

`"log"(K_(2))/(K_(1))=(E_(a))/(2.303R)[(1)/(T_(1))-(1)/(T_(2))]`
`log10^(-1)=(E_(a))/(2.303R)[(1)/(300)-(1)/(270)]`
`E_(a)=(2.303Rxx270xx300)/(30)J//mol`
`=2.303xx2.7R" "kJ//mol`