Oxidation number if iodine in `IO_(3)^(-), IO_(4)^(-),KI and I_(2)` respectively are

Options

A. `-1,-1,0,+1`
B. `+3,+5,+7,0`
C. `+5,+7,-1,0`
D. `-1,-5,-1,0`

Answer

C

Explanation

Oxidation state of l in `lO_(3)^(-)`
`x+(-2)3=-1impliesx=+5`
Oxidation state of l in `lO_(4)^(-)`
`x+(-2)4=-1impliesx=+7`
Oxidation state of l in kl
`+1+x=0impliex=-1`
Oxidation state of l in `l_(2)x=0`
Hence, the oxidation number of iodine in `lO_(3)^(-),lO_(4)^(-),Kl and l_(2)` are respectively +5, +7, -1 and 0.