The rate of cooling at 600 K, if surrounding temperature is 300 K is R. The rate of cooling at 900 K is

Options

A. `(16)/(3)R`
B. 2R
C. 3R
D. `(2)/(3)R`

Answer

B

Explanation

Rate of cooling `prop(T^(4)-T_(0)^(4))`
`rArr (R_(1))/(R_(2))=((T_(1)^(4)-T_(0)^(4)))/(T_(2)^(4)-T_(0)^(4))`
`rArr (R)/(R_(2))((600)^(4)-(300)^(4))/((900)^(4)-(300)^(4))`
or `R_(2)=(16)/(3)R`