Area of a parallel plate capacitor of capacitance 2F and separation between the plates `0.5cm` will be

Options

A. `1.13xx10^(9) m^(2)`
B. `1.13xx10^(6) m^(2)`
C. `10^(8) m^(2)`
D. `1.13 m^(2)`

Answer

A

Explanation

Here, `C=2 F,d =0.5 cm`
`0.5xx10^(-2)m`,
`epsi_(0)=8.854xx10^(-12)C^(2)//Nm^(2)`
`:. C=(epsi_(0)A)/(d)`
or `A=(Cd)/(epsi_(0))=(2xx0.5xx10^(-2))/(8.854xx10^(-12))`
`=1.13xx10^(9)m^(2)`