If the equation for the displacement of a particle moving in a circular path is given by `(theta)=2t^(3)+0.5`, where `theta` is in radians and `t` in seconds, then the angular velocity of particle after `2 s` from its start is

Options

A. 8 rad/s
B. 12 rad/s
C. 24 rad/s
D. 36 rad/s

Answer

C

Explanation

Angular velocity is,
`omega=(domega)/(dt)=(d)/(dt)(2t^(3)+0 5)=6t^(2)`
at `t=2s`
`omega=6xx(2)^(2)=24` rads/s