A mass of 10 kg is suspended from a spring balance. It is pulled aside by a horizontal string so that it makes an angle of `60^(@)` with the vertical. The new rading of the balance is

Options

A. 20 kg-wt
B. 10 kg-wt
C. `10 sqrt(3)` kg-wt
D. `20sqrt(3)` kg-wt

Answer

A

Explanation

The situations is shown in figure at an angle of `60^(@)`
`T cos theta= mg`
`T=(mg)/(cos theta)=(10g )/( cos 60^(@))`
`10//_(1_//2)=20 kg -omega t`