Two blocks 4 kg and 2 kg are sliding down an incline plane as shown in figure. The acceleration of 2 kg block is.

Options

A. `1.66 m//s^(2)`
B. `2.66 m//s^(2)`
C. `3.66 m//s^(2)`
D. `4.66 m//s^(2)`

Answer

B

Explanation

Let contact force =R
`m_(1)g sin alpha- R mu_(1) N_(1)= m_(1) a " "...(i)`
`R((mu_(2)-mu_(1))m_(1)m_(2)g cos alpha)/((m_(1)+m_(2)))" "...(i)`
`R=(0.1xx8xx9.8xxsqrt((3)/(2)))/(6)`

On simplify Eqa. (i) and (ii) we get `=2.64 m//s^(2)`