A particle in SHM has maximum velocity equals to 36 m/s and maximum acceleration of `216 pi m//s^(2)`. The time period of SHM will be

Options

A. `(1)/(3)s`
B. `3pi s`
C. `6 pi s`
D. `3s`

Answer

A

Explanation

As, `v_("max")= a omega =36 m//s`
and `alpha_("max")= a omega^(2)=216 pi m//s^(2)`
`:. Omega=6pi`
`rArr T=(2pi)/(omega)=(2pi)/(6 omega)=(1)/(3)s`