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A stretched string fixed at both end has...

A stretched string fixed at both end has n nods, then the lengths of the string is

A

`(n-1) (lambda)/(2)`

B

`(3n+1) (lambda)/(2)`

C

`(n+1) (lambda)/(2)`

D

`5((n+1)lambda)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Paris of noede `=(n-1)`
length of the string `=(n-1)(lambda)/(2)`
(as length from node to node is `(lambda)/(2))`
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