A liquid of density `800kgm^(-3)` is filled in a tank open at the top. The pressure of the liquid at the bottom of the tank is 6.4 atm. The velocity of efflux through a hole at the bottom is (1 atm `=10^(4)Nm^(-2)`)

Options

A. `10ms^(-1)`
B. `20ms^(-1)`
C. `30ms^(-1)`
D. `40ms^(-1)`

Answer

D

Explanation

Velocity of efflux `V=sqrt(2gh)`
But `h rho g=P`
`hg=p/(rho)`
`V=sqrt((2P)/(rho))=sqrt((2xx6.4xx10^(5))/800)m//s`
`=40m//s`