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An air capacitor of capacity C = 10 mu F...

An air capacitor of capacity `C = 10 mu F` is connected to a constant voltage battery of `12 V`. Now the space between the plates is filled with a liquid of dielectirc constant `5`. The charge that flows now from battery to the capacitor is

A

`40muC`

B

`480muC`

C

`600muC`

D

`120muC`

Text Solution

Verified by Experts

The correct Answer is:
B
Case I `Q_(1)=C_(1)V`
`=10xx12=120muC`………..i
`C_(2)=KC_(1)=5xx10=50muF`…….ii
Case II `Q_(2)=C_(2)V`
`=50xx12=600muC`
Hence `Q=Q_(2)-Q_(1)`
`:.=600-120=480muC`
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