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A steel wire 0.5 m long has a total mass...

A steel wire 0.5 m long has a total mass of 0.02 kg and is stretched with a tension of `800N`. The frequency when it vibrates in its fundamental mode is

A

`2Hz`

B

`141Hz`

C

`100Hz`

D

`200Hz`

Text Solution

Verified by Experts

The correct Answer is:
B
Mass per unit length,
`m=0.02/0.5kg//m`
length `L=0.5m`
Tension `T=850N`
So, fundamental frequency of a wire is given by
`v=1/(2L)sqrt(T/m)=1/(2xx0.5)sqrt(800/0.04)`
`=141Hz`
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