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Young's double slit experimental arrangement is shown in figure. If `lamda` is the wavelength of light used and `angleS_(1)CS_(2)=theta`, then the fringe width will be

A

`(lamda)/(theta)`

B

`(lamda)/(2theta)`

C

`lamdatheta`

D

`(2lamda)/(theta)`

Text Solution

Verified by Experts

The correct Answer is:
A
Fringe width, `beta=(Dlamda)/(d)`
But here, `theta=(d)/(D)impliesd=D theta`
`therefore beta=(D lamda)/(D theta)=(lamda)/(theta)`
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