A man slides down on a telegraphic pole with an acceleration equal to one-fourth of acceleration due to gravity.The frictional force between man and pole is equal to (in terms of man's weight `W`)

Options

A. `(w)/(4)`
B. `(w)/(2)`
C. `(3w)/(4)`
D. `w`

Answer

C

Explanation

Man is sliding down the telegraphic pole with acceleration g/4.
So, `mg-F=(mg)/(4)`
`impliesF=mg-(mg)/(4)`
`impliesF=(3mg)/(4)`
`impliesF=(3w)/(4)`