The unit of Stefan's constant `sigma` is

Options

A. `Wm^(-2)//k`
B. `Wmk^(-4)`
C. `Wm^(-2)//k^(4)`
D. `Mn^(-2)//k^(4)`

Answer

C

Explanation

According to Stefan's law, the energy radiated per second or power radiated is given by
`P=sigmaAT^(4)`
`implies sigma=(P)/(AT^(4))`
Therefore, the unit of
`sigma=(W)/(m^(2)K^(4))=Wm^(-2)K^(-4)`
Therefore, the unit of
`sigma=(W)/(m^(2)K^(4))=Wm^(-2)K^(-4)`