A black body radiates energy at the rate of `EW//m^(2)` at a high temperature TK. When the temperature is reduces to half, the radiant energy will be

Options

A. `(E)/(16)`
B. `(E)/(4)`
C. `4E`
D. `16E`

Answer

A

Explanation

We know that
`E propT^(4)`
Hence, `(E_(1))/(E_(2))=(T^(4))/((T//2)^(4))implies`
`E_(2)=(E)/(16)`