If a committee of 3 is to be chosen from a group of 38 people of which you are a member. What is the probability that you will be on the committee?

Options

A. `((38)/(3))`
B. `((37)/(2))`
C. `((37)/(2))//((38)/(2))`
D. `(666)/(8436)`

Answer

D

Explanation

From the given condition it is clear that a particular person is always is a committee of 3 person is always in a committee of 3 person. It means we have to select 2 person out of 37 person.
`therefore` Required probability ,brgt `=(.^(37)C_(2))/(.^(38)C_(3))=(666)/(8436)`