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The bisector of the acute angle formed b...

The bisector of the acute angle formed between the lines 4x - 3y + 7 = 0 and 3x - 4y + 14 = 0 has the equation

A

x+y+3=0

B

x-y-3=0

C

x-y+3=0

D

3x+y-7=0

Text Solution

Verified by Experts

The correct Answer is:
C
The equation of bisector of acute angle formed between the lines 4x-3y+7=0
and 3x-4y+14=0 is
`(4x-3y+7)/(sqrt(16)+9)=(3x-4y+14))/(sqrt(16+9))" "[because a_(1)a_(2)+b_(1)b_(2)gt0]`
`implies7x-7y+21=0`
`impliesx-y+3=0`
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