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In order to eliminate the first degree terms from the equation `2x^(2)-4xy+5y^(2)-4x-2y+7=0` then point to which origin is to be shifted is

A

(1,-3)

B

(2,3)

C

(-2,3)

D

(1,3)

Text Solution

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The correct Answer is:
C

Here `a=2, b=5,c=7`
`h=2,g=-2,f=-11`
to eliminate 1st degree terms origin is to be shifted to the point
`(hf-bg)/(ab-h^(2)),(gh-af)/((ab-h^(2)))`
`=((-22+10)/(10-4),(-4+22)/(10-4))`
`=(-2,3)`
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