Home
Class 12
MATHS
The equation of the parabola whose focus...

The equation of the parabola whose focus is (3,-4) and direction `6x-7y+5=0` is

A

`(7x+6y)^(2)-570x+750y+2100=0`

B

`(7x+6y)^(2)+570x-750y+2100=0`

C

`(7x-6y)^(2)-570x+750y+2100=0`

D

`(7x-6y)^(2)+570x-750y+2100=0`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the parabola with a focus at (3, -4) and a directrix given by the line \(6x - 7y + 5 = 0\), we will follow these steps: ### Step 1: Identify the focus and the directrix The focus of the parabola is given as \(F(3, -4)\). The equation of the directrix is \(6x - 7y + 5 = 0\). ### Step 2: Find the distance from a point \((x, y)\) to the focus The distance \(d_F\) from a point \((x, y)\) to the focus \((3, -4)\) can be calculated using the distance formula: \[ d_F = \sqrt{(x - 3)^2 + (y + 4)^2} \] ### Step 3: Find the distance from a point \((x, y)\) to the directrix The distance \(d_D\) from the point \((x, y)\) to the line \(6x - 7y + 5 = 0\) can be calculated using the formula for the distance from a point to a line: \[ d_D = \frac{|6x - 7y + 5|}{\sqrt{6^2 + (-7)^2}} = \frac{|6x - 7y + 5|}{\sqrt{36 + 49}} = \frac{|6x - 7y + 5|}{\sqrt{85}} \] ### Step 4: Set the distances equal For a point to lie on the parabola, the distance to the focus must equal the distance to the directrix: \[ \sqrt{(x - 3)^2 + (y + 4)^2} = \frac{|6x - 7y + 5|}{\sqrt{85}} \] ### Step 5: Square both sides to eliminate the square root Squaring both sides gives: \[ (x - 3)^2 + (y + 4)^2 = \frac{(6x - 7y + 5)^2}{85} \] ### Step 6: Multiply through by 85 to eliminate the fraction \[ 85[(x - 3)^2 + (y + 4)^2] = (6x - 7y + 5)^2 \] ### Step 7: Expand both sides Expanding the left side: \[ 85[(x^2 - 6x + 9) + (y^2 + 8y + 16)] = 85(x^2 + y^2 - 6x + 8y + 25) \] \[ = 85x^2 + 85y^2 - 510x + 680y + 2125 \] Expanding the right side: \[ (6x - 7y + 5)^2 = 36x^2 - 84xy + 49y^2 + 60x - 70y + 25 \] ### Step 8: Set the expanded forms equal Setting both expanded forms equal: \[ 85x^2 + 85y^2 - 510x + 680y + 2125 = 36x^2 - 84xy + 49y^2 + 60x - 70y + 25 \] ### Step 9: Rearranging the equation Rearranging gives: \[ (85x^2 - 36x^2) + (85y^2 - 49y^2) + (510x + 60x) + (680y + 70y) + (2125 - 25) = 0 \] \[ 49x^2 + 36y^2 - 570x + 750y + 2100 = 0 \] ### Final Equation The equation of the parabola is: \[ 49x^2 + 36y^2 - 570x + 750y + 2100 = 0 \]

To find the equation of the parabola with a focus at (3, -4) and a directrix given by the line \(6x - 7y + 5 = 0\), we will follow these steps: ### Step 1: Identify the focus and the directrix The focus of the parabola is given as \(F(3, -4)\). The equation of the directrix is \(6x - 7y + 5 = 0\). ### Step 2: Find the distance from a point \((x, y)\) to the focus The distance \(d_F\) from a point \((x, y)\) to the focus \((3, -4)\) can be calculated using the distance formula: \[ ...
Promotional Banner

Topper's Solved these Questions

  • PRACTICE SET 11

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PAPER 2 (MATHEMATICS )|50 Videos
  • PRACTICE SET 13

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PAPER II OBJECTIVE TYPE|50 Videos

Similar Questions

Explore conceptually related problems

Find the equation of the parabola whose focus is (-3, 4) and directrix x - y + 5 = 0.

The equation of the parabola whose focus is (-3,0) and the directrix is x+5=0 is:

The equation of the parabola whose focus is (-3,0) and the directrix is, x+5=0 is:

An equation of the parabola whose focus is (-3,0) and the directrix is x +5=0 is :

Find the equation of the parabola whose focus is (2, 3) and directrix is x-2y-6=0 .

Find the equation of the parabola whose focus is (-1, 2) and directrix is x-2y-15=0 .

Find the equation of the parabola whose focus is (6, 0) and directrix is x = -6 .

Find the equation of the parabola whose focus is (0,-4) and directrix is y=4.

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-PRACTICE SET 12-Paper 2 (Mathematics)
  1. The area under the curve y+sqrt(3) sin x=sin 2x between the ordinates ...

    Text Solution

    |

  2. int(1-cosx)cosec^(2)x dx is equal to

    Text Solution

    |

  3. The system of equations x+y+z=5, x+2y+lamdaz=mu, x+2y+3z=9 has (i)...

    Text Solution

    |

  4. Find the general solution of the differential equations sec^2xtany dx...

    Text Solution

    |

  5. sin[3sin^(-1)((1)/(5))] is equal to

    Text Solution

    |

  6. If f:RtoR is defined by f(x)=|x|, then

    Text Solution

    |

  7. The equations of the circle which pass through the origin and make int...

    Text Solution

    |

  8. A circle with centre at (2, 4) is such that the line x+y+2= 0 cuts a ...

    Text Solution

    |

  9. The equation of the parabola whose focus is (3,-4) and direction 6x-7y...

    Text Solution

    |

  10. The equation (x^(2))/(2-lamda)-(y^(2))/(lamda-5)-1=0, represent and el...

    Text Solution

    |

  11. If x^my^n = (x + y)^(m+n), then (dy/dx)(x=1, y=2) is equal to

    Text Solution

    |

  12. If f'(x)=sin(log x)and y=f((2x+3)/(3-2x)), then dy/dx equals

    Text Solution

    |

  13. If the mean and the variance of a binomial variable X are 2 and 1 resp...

    Text Solution

    |

  14. Twelve tickets are numbered from 1 to 12. One ticket is drawn at rand...

    Text Solution

    |

  15. The area enclosed between the curves y = x^(3) and y = sqrt(x) is

    Text Solution

    |

  16. Write the angle between the line (x-1)/2=(y-2)/1=(z+3)/-2 and the plan...

    Text Solution

    |

  17. The number of distinct values of lamda, for which the vectors -lamda^(...

    Text Solution

    |

  18. The solution of the differential equation (dy)/(dx)=(x-y+3)/(2x(x-y)+5...

    Text Solution

    |

  19. The general solution of equation 3 tan(theta - 15^o) = tan(theta+15^o)...

    Text Solution

    |

  20. The mean and standard deviation of a binomial variate X are 4 and 3 re...

    Text Solution

    |