The moment of inertia of a circular loop of radius R, at a distance of `R//2` around a rotating axis parallel to horizontal diameter of loop is

Options

A. `MR^(2)`
B. `1/2MR^(2)`
C. `2MR^(2)`
D. `3/4MR^(2)`

Answer

D

Explanation

Applying theorem of parallel axis,
`l=l_(CM)+M(R/2)^(2)`
`=l=1/2MR^(2)+(MR^(2))/4` or `l-3/4MR^(2)`