A particle is moving along a circular along a circular path of radius 5 m with a uniform speed `5ms^(-1)`. What will be the average acceleration when the particle completes half revolution?

Options

A. Zero
B. `10" m"//"s"^(2)`
C. `10pi" m"//"s"^(2)`
D. `(10)/(pi)"m"//"s"^(2)`

Answer

D

Explanation

When the particle completes half revolution, then change in velocity
`Deltav=[5-(-5)]"m"//"s"=10" m"//"s"`
Time taken to complete the half revolution is
`t=(pi" r")/(v)=(pixx5)/(5)=pisec`
Thus, average acceleration
`=(Deltav)/(t)=(10)/(pi)"m"//"s"^(2)`