A particle is moving along a circular al...

A particle is moving along a circular along a circular path of radius 5 m with a uniform speed `5ms^(-1)`. What will be the average acceleration when the particle completes half revolution?

Zero

`10" m"//"s"^(2)`

`10pi" m"//"s"^(2)`

`(10)/(pi)"m"//"s"^(2)`

Text Solution

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The correct Answer is:

When the particle completes half revolution, then change in velocity
`Deltav=[5-(-5)]"m"//"s"=10" m"//"s"`
Time taken to complete the half revolution is
`t=(pi" r")/(v)=(pixx5)/(5)=pisec`
Thus, average acceleration
`=(Deltav)/(t)=(10)/(pi)"m"//"s"^(2)`

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A particles is moving along a circular path of radius 5 m , moving with a uniform speed of 5ms^(-1) . What will be the avetage acceleration, Whan the particle completes half revolution?

zero

`10pims^(-2)`

`pi//ms^(-2)`

None of these

A partical is moving along a circular path of radius 5m and with uniform speed 5 m//s . What will be the avarage acceleration when the partical completes half revoluation?

zero

`10m//s^(2)`

`10pm//s^(2)`

`(10//pi)m//s^(2)`

A particle is moving along a circular path of radius 6 m with uniform speed of 8 ms^(–1) . The average acceleration when the particle completes one half of the revolution is -

`(16)/(3pi)m//s^(2)`

`(32)/(3pi) m//s^(2)`

`(64)/(3pi)m//s^(2)`