Two pendulums have time period T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation ?

Options

A. `45^(@)`
B. `90^(@)`
C. `60^(@)`
D. `30^(@)`

Answer

B

Explanation

When bigger pendulum of time period `(5T//4)` completes one vibration, the smaller pendulum will complete `(5//4)` vibrations. It means the smaller pendulum will be leading the bigger pendulum by phase `T//4` second `=pi//2` rad `=90^(@)`