For a particle executing `S.H.M.,` the kinetic energy `K` is given `K = K_(0) cos ^(2)omega t`. The maximum value of potential energy is:

Options

A. `K_(0)`
B. zero
C. `K_(0)//2`
D. not obtainable

Answer

A

Explanation

`K_("max")=K_(0)=` total energy As total energy remains conserved in SHM, hence when `U` is maximum in SHM, `K=0` i.e. `E` is also equal to `U_("max")` i.e. `U_("max")=E=K_(0)`