A water drop is divided into 8 equal droplets. The pressure difference between the inner and outer side of the big drop will be

Options

A. same as for smaller droplet
B. `1/2` of that for smaller droplet
C. `1/4` of that for smaller droplet
D. twice that for smaller droplet

Answer

B

Explanation

Volume of big drop`=` Volume of 8 droplets
i.e. `4/3piR^(3)=8xx4/3pir^(3)`
`:.r=R/2`
For smaller drop,
`Delta p_(s)=(2T)/r=(2T)/(R//2)=(4T)/R`
For bigger drop
`Delta p_(b)=(2T)/R=1/2 Delta p_(s)`