On increasing the plate separation of a charged condenser, the energy

Options

A. increases
B. decreases
C. remains unchanged
D. becomes zero

Answer

A

Explanation

The energy which is stored int eh capacitor is given by
`e=1/2 . (q^(2))/C`……….i
where `q` is charge and C the capacitance.
Also `C=(epsilon_(0)A)/d`
From eqs (i) and (ii) we get
`E=1/2 . (q^(2)d)/(epsilon_(0)A)`
`impliesEpropd`
When plate separation (d) is increased energy increases.