A capacitor having capacity of `2 muF` is charged to `200 V` and then the plates of the capacitor are connected to a resistance wire. The heat produced in joule will be

Options

A. `2xx10^(-2)`
B. `4xx10^(-2)`
C. `4xx10^(4)`
D. `4xx10^(10)`

Answer

B

Explanation

Heat produced in a wire is equal to energy stored in capacitor.
`E=H=1/2 CV^(2)`
`=1/2xx(2xx10^(-6))xx(200)^(2)`
`=(10^(-6)xx200xx200`
`=4xx10^(-2)J`