If the momentum of a body is increased by 50%, then the percentage increase in its kinetic energy is

Options

A. 1
B. 2.5
C. 4
D. 5

Answer

C

Explanation

Ratio of the radiated power is
`(E_(1))/(E_(2))=[T/(T+T/2)]^(4)=[T/(3T//2)]^(4)=16/81`
% increse in `E=(E_(2)-E_(1))/(E_(1))xx100`
`=(81/16E_(1)-E_(1))/(E_(1))xx100=400%`