When rusting starts,

Options

A. `Fe^(2)`, ions pass into solution at cathodic area
B. `H^(+)` ions reduced to `H_(2)` gas at anodic area
C. oxygen in the presence of `H^(+)` ions, reduces to water at cathodic area
D. oxygen in the presence of `H^(+)` ions reduces of water at anodic area

Answer

C

Explanation

Electrolytic solution
`H_(2)CO_(3)hArr2H^(+)+CO_(3)^(2-)`
`["air"-CO_(2)+O_(2)+H_(2)O]`
`Fe` in contact with `O_(2)` and presence of `H^(+)` ions undergoes oxidation.
Anode, `FetoFe^(2+)+2e^(-)`
`(E^(@)=-0.44V)`
Cathode
`O_(2)+4H^(+)+4e^(-)to2H_(2)O`
`(E^(@)=1.23V)`