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If standard electrode potenial of Cu^(2+...

If standard electrode potenial of `Cu^(2+)//Cu` is `0.34V` then potential of `Cu` dipped in 0.1 M solution of `CuSO_(4)` will be

A

`0.34 V`

B

`-0.34 V`

C

`0.31V`

D

`-0.31V`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=E^(@)=0.059/n"log"_(10)[Cu^(+2)]`
`=0.34-0.059/2"log"_(10)1/0.1`
`=0.31V`
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