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If f(x)={sinx ,x!=npi,n in I2,ot h e r ...

If `f(x)={sinx ,x!=npi,n in I2,ot h e r w i s e` `g(x)={x^2+1,x!=0,4,x=0 5,x=2` then `("lim")_(xvec0)g{f(x)}i s=`

A

`1`

B

`0`

C

`1/2`

D

`1/4`

Text Solution

Verified by Experts

The correct Answer is:
A

`lim_(xto0)g{f(x)}=lim_(xto0){f(x)}^(2)+1`
`=lim_(xto0)sin^(2)x+1=1`
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