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if |veca|=4, |vecb|=2 and the angle betw...

if` |veca|=4, |vecb|=2` and the angle between `veca and vecb` is ` pi/6` then `(vecaxxvecb)^2` is equal to

A

48

B

16

C

a

D

None of these

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The correct Answer is:
B
Given that `|a|-4,|b|=2` and `theta=(pi)/6`
`:.(axxb)^(2)(|a|.|b|sintheta)^(2)`
`=(4.2sin 30^(@))^(2)`
`=(8 .1/2)^(2)=(4)^(2)=16`
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