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A point mass of 2 kg tied to a stri...

A point mass of 2 kg tied to a string of 1 m length is rotated in a vertical circle with uniform speed of 4m/s. The tension in the string is nearly 32 N when mass is at

A

botton

B

mid- way

C

highest point

D

between bottom and mid way

Text Solution

Verified by Experts

The correct Answer is:
A
Tenesion in the string at any point is
` T - mg cos theta = ( mv ^ 2 )/( r ) `
` rArr T= ( mv ^ 2 ) /( r ) + mg cos theta `
` rArr 52 = ( 2xx 16 )/( 1 ) + 2xx 10 cos theta `
` = 22 + 20 cos theta `
` rArr 20 = 20 cos theta `
` rArr cos theta = 1 `
` rArr theta = 0^@ `
` therefore ` Mass is at the bottom of circle.
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Knowledge Check

  • A mass of 2 kg tied to a string 1 m length is rotate in a verticle circle with a uniform speed of 4 m//s . The tension in the string will be 52 N, when the mass is at (g=10 m//s^(2))

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