If `E` = energy , `G`= gravitational constant, `I`=impulse and `M`=mass, then dimensions of `(GIM^(2))/(E^(2)` are same as that of

Options

A. time
B. mass
C. length
D. force

Answer

A

Explanation

Dimension of `E=[ML""^(2)T^(-2)]`
Dimension of `G=[(Fd^(2))/(m_(1)m_(2))]`
`=[M^(-1)L^(3)T^(-2)]`
Dimension of `l=["Force"xx"time"]`
`=["MLT"^(-1)]`
and Dimension of M = [M]
`:.` Dimension of `("GlM"^(2))/(E^(2))`
`=([M^(-1)L^(3)T^(-2)]*[MLT^(-1)][M^(2)])/([ML^(2)T^(-2)]^(2))`
`=[T]`