Two gases A and B having the same temperature T, same pressure P and same volume V are mixed. If the mixture is at the same temperature and occupies a volume V. The pressure of the mixture is

Options

A. `2p`
B. p
C. p/2
D. 4p

Answer

A

Explanation

We know that,
`p_(1)V_(1)=p_(2)V_(2)," "p_(2)=(p_(1)V_(1))/(V_(2))`
Given `" "p_(1)=p,V_(1)=V+V=2V`
`V_(2)=V`
`implies" "p_(2)=(pxx2V)/(V)" or "p_(2)=2p`