If the angle between the pass axis of polariser and analyser is `45^(@)`, write the ratio of intensities of original light and the transmitted light after passing through analyser.

Options

A. `(l)/(2)`
B. `(l)/(3)`
C. l
D. `(l)/(4)`

Answer

D

Explanation

Given that, angle between pass axis of polariser and the analyser, `phi=45^(@)` the intensity of the light after passing through the polariser
So, `l=l_(0)cos^(2)phi=l_(0)cos^(2)45^(@)`
`=l_(0)((1)/(sqrt(2)))^(2)=(l)/(2)xx(1)/(2)=(1)/(4)"("becausel_(0)=(l)/(2)")"`