If work `W` is done in blowing a bubble of radius `R` from a soap solution. Then the work done is blowing a bubble of radius `2R` from the same solution is

Options

A. `2^(1//3)` W
B. 4 W
C. 2 W
D. `(W)/(2)`

Answer

B

Explanation

Required work done is `W=8piR^(2)T`
and `" "W'=8pi(2R)^(2)T`
`(W')/(W)=(4)/(1)`
`implies" "W'=4W`