Two light waves of amplitudes `A_(1)` and `A_(2)` superimpose with each other such that `A_(1) gt A_(2)`. The difference between maximum and minimum amplitudes is

Options

A. `A_(1)`
B. `2A_(2)`
C. `2A_(1)`
D. `A_(2)`

Answer

B

Explanation

The maximum amplitude is written by 30.
`A_("max")=A_(1)+A_(2)`
and the minimum amplitude is
`A_("min")=A_(1)-A_(2)`
Their corresponding difference is
`A_("max")-A_("min")=A_(1)+A_(2)-(A_(1)-A_(2))`
`=2A_(2)`