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The magnetic flux linked with a coil at ...

The magnetic flux linked with a coil at any instant 't' is given by `phi = 5t^3 - 100 t+300`, the e.m.f. induced in the coil at t = 2 second is

A

40 V

B

`-40 "V"`

C

300 V

D

140 V

Text Solution

Verified by Experts

The correct Answer is:
A

The induced emf `e=-(d phi)/(dt)`
So, `" "e=-(d)/(dt)(5t^(3)-100t+300)`
or `" "e=-(15t^(2)-100)`
Induced emf at t = 2 s
`e=-(15xx4-100)=+40`
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