Probability of throwing 16 in one throw with there dice is

Options

A. `1/36`
B. `1/18`
C. `1/72`
D. `1/9`

Answer

A

Explanation

The total number of possible ways
` n (S ) = 6 xx 6 xx 6 = 216 `
Now, we find out how many ways are favourable to the total of 16 points in one throw. Let A, B, and C be the three dice, then favourable ways happen only as follows :
` ( 6,6,4 ),( 6,4,6 ) , ( 6,5,5) ,( 5,5,6) , ( 5,6,5 ) ,(4,6,6) `
Hence, the total number of favourable ways ` n (A) = 6 `
` therefore ` Requied pobability
` = ( n(A))/( n(S)) = ( 6 ) /( 216) = ( 1 )/( 36 ) `