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The probability of choosing a number div...

The probability of choosing a number divisible by 6 or 8 from among 1 to 90 is

A

`1/6`

B

`1/90`

C

`1/30`

D

`23/90`

Text Solution

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The correct Answer is:
D
Total number =90
Numbers divisible by 6 are `{ 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90 } `
Numbers divisible by 8 are ` {8,16,24, 32,40,48,56,64,72,80,88} `
Numbers divisible by 6 and 8 are `{ 24,48,72}`
Total number of numbers divisible by 6 or 8
` = 15 + 11 - 3 = 23 `
` therefore ` Required probability = ` (23 )/( 90) `
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