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An integrating factor of the differentia...

An integrating factor of the differential equation
`ylogy(dx)/(dy)+x-logy=0`, is

A

`(1)/(logy)`

B

`log (log y)`

C

`1+log y`

D

`logy`

Text Solution

Verified by Experts

The correct Answer is:
D

Given differential equation can be rewritten as
` (dx ) /( dy ) = ((log y - x ) ) /( y log y ) `
` rArr (dx)/(dy)+ ( x ) /( y log y ) = ( 1 )/( y ) `
` therefore IF = e ^( int ( 1 )/( y log y ) dy ) `
` = e ^( log log y ) = log y `
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